JackCraftSolar
n! ≈ √(2πn) ⋅ (n/e)ⁿ is Sterling's Approximation, which can be used to Approxmate n! for very large nn = any numberFor example:if n = 2000, the formula tells us:2000! ≈ 1.2877 × 10^5739
7 months ago | [YT] | 2
JackCraftSolar
n! ≈ √(2πn) ⋅ (n/e)ⁿ is Sterling's Approximation, which can be used to Approxmate n! for very large n
n = any number
For example:
if n = 2000, the formula tells us:
2000! ≈ 1.2877 × 10^5739
7 months ago | [YT] | 2