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6 days ago
| 10
KON KON AGREE KARTA HAI KI CORRECT OPTION (C) for IIT Chennai hai 😅
5 days ago | 193
C kyuki jaise acceleration upar jayega who 3a - a hoga aur jaise denominator me Jayega wo plus ho jayega
5 days ago | 18
Either balancing the forces, or conserving acceleration of centre of mass since no external force is acting on it option C is correct
5 days ago (edited) | 14
Let the force(Byount force or anything due to which it goes up) be F . Then F-Mg=Ma . Now let m mass is released from the Ballon. So now F-(M-m)g=(M-m)3a. Solve both the equation to get the value of small m.
5 days ago | 10
Option C because the ballon is moving in a accelerated frame with the acceleration 3a. So net acceleration is 3a +g. JUST CHECKING THE DENOMINATOR OPTION C IS CORRECT
4 days ago (edited) | 1
JEE Wallah
Chalo dekhein tum log ye sawal ka jawab sahi de pate ho ya nahi? Comment down your answer 👇🏻
6 days ago | [YT] | 2,550