Invidious

https://youtu.be/aPsFlFk20cE?si=V-kF3...

7 months ago | [YT] | 124

x ^ √(x) = √(x ^ x) = x ^ (x / 2) log(x ^ √(x)) = log(x ^ (x / 2)) √(x) * log(x) = x / 2 * log(x) √(x) * log(x) - x / 2 * log(x) = 0 log(x) * (√(x) - x / 2) = 0 Case 1: log(x) = 0 x = 1 Case 2: √(x) - x / 2 = 0 √(x) = x / 2 x = x² / 4 (x ≥ 0) 4 * x = x² x² - 4 * x = 0 x * (x - 4) = 0 Case 2.1: x = 0 x ^ √(x) = √(x ^ x) = 0 ^ 0 (Indetermination) x ≠ 0 Case 2.2: x - 4 = 0 x = 4 Possible solutions: 1, 4

7 months ago (edited) | 8

@mehdizangiabadi-iw6tn

z=x^2+y^2+z^2

6 months ago | 1

@sahilderle942

Bhai arthematico geometric sequences sum of infinity terms ka formula ka koi 1 or 2 question solve karke video bejo please bhai

7 months ago | 2

@mehdizangiabadi-iw6tn

x^√3x=x

6 months ago | 1

@arifariffulislam2246

Who do you think I am ?

7 months ago | 2

@PadhnaHaPhodnaHa

1/4

7 months ago | 1

@mehdizangiabadi-iw6tn

(x^2)/8;(x^2)/α

6 months ago | 1

@matei_woold_wewu

x1=1 x2=4

7 months ago | 0

@amorecredibleusername692

x^sqrt(x) = sqrt(x^x) x^2sqrt(x)=x^x 2sqrt(x)=x sqrt(x)=(x/2) x=0,4

7 months ago | 1

@mehdizangiabadi-iw6tn

-1<(x;y)<1

6 months ago | 0

x^(√x) = √(x^x) x^(2√x) = x^x 2√x = x 4x = x^2 x^2 - 4x = 0 x = (4 +- √16)/2 x = (4 +- 4)/2 x = 2 +- 2 x = 0; 4

7 months ago | 3

@mitclashers

1,0,4

7 months ago | 1