MohaMyers
*Michael ripping a stainless steel bed**Overall bed size*- Length: 2meters (+)- Width: 0.9 meter- Steel frame tube: 30×60mm to 75 + wall thickness 1-2 mm- sheet thickness: 1 mm (+)- Main steel frame and welded joints and rectangular/round steel tubing, welded. This is the structural backbone of Tearing subjects:*Convert 400 kg into force:*- 1. 400 × 9.81 = (?)- 400 × 9 = 3,600- 400 × 0.81 = 324- 3,600 + 324 = 3,924 N (≈ 3.9 kN)- So vertical lifting peak ≈ 4 kN for a top lifter in that example.*Estimates for ripping actions**Snapping plastic panel / removing trims* Class 5- Force needed: ~100–1,000 N (0.1–1.0 kN). Class 5*Bending and popping a side-rail*- Typical hand push force: say 1,500–2,000 N (1.5–2.0 kN) Class 5 *bending moment = force × lever arm*- Example: 2,000 × 0.5 = (?)- 2,000 × 0.5 = 1,000 N·m*1,000 N·m of moment can bend many thin rails Strongman+leverage can achieve this**Shearing a welded frame joint or ripping major tubing out of the frame*- Steel weld example (illustrative): assume a weld throat thickness of 5 mm (0.005 m) over a 300 mm (0.30 m) length.- Weld cross-sectional area = thickness × length = 0.005 × 0.30 = (?)- 0.005 × 0.30 = 0.0015 m²- If mild steel ultimate shear strength ~ 250 MPa (250,000,000 N/m²), force to shear that weld ≈ stress × area you're gonna need:- 250,000,000 × 0.0015 = (?)- 250,000,000 × 0.001 = 250,000- 250,000,000 × 0.0005 = 125,000- 250,000 + 125,000 = 375,000 N (≈ 375 kN) or Class 5 (+)
3 days ago | [YT] | 14
@MKX67
Damn my boi strong asf
3 days ago | 2
@SubZeroMKfans
Damn, W
3 days ago | 1
@Ksfgxm12
Gpt😭
23 hours ago | 1
View 1 reply
@TheOfficialCoolboy1817
Dang, I bet Michael Myers worked out and drink a lot of protein at the same time because he built like that with a lot of muscle if he could pull it off like that 😂😂😂
MohaMyers
*Michael ripping a stainless steel bed*
*Overall bed size*
- Length: 2meters (+)
- Width: 0.9 meter
- Steel frame tube: 30×60mm to 75 + wall thickness 1-2 mm
- sheet thickness: 1 mm (+)
- Main steel frame and welded joints and rectangular/round steel tubing, welded. This is the structural backbone of Tearing subjects:
*Convert 400 kg into force:*
- 1. 400 × 9.81 = (?)
- 400 × 9 = 3,600
- 400 × 0.81 = 324
- 3,600 + 324 = 3,924 N (≈ 3.9 kN)
- So vertical lifting peak ≈ 4 kN for a top lifter in that example.
*Estimates for ripping actions*
*Snapping plastic panel / removing trims* Class 5
- Force needed: ~100–1,000 N (0.1–1.0 kN). Class 5
*Bending and popping a side-rail*
- Typical hand push force: say 1,500–2,000 N (1.5–2.0 kN) Class 5
*bending moment = force × lever arm*
- Example: 2,000 × 0.5 = (?)
- 2,000 × 0.5 = 1,000 N·m
*1,000 N·m of moment can bend many thin rails Strongman+leverage can achieve this*
*Shearing a welded frame joint or ripping major tubing out of the frame*
- Steel weld example (illustrative): assume a weld throat thickness of 5 mm (0.005 m) over a 300 mm (0.30 m) length.
- Weld cross-sectional area = thickness × length = 0.005 × 0.30 = (?)
- 0.005 × 0.30 = 0.0015 m²
- If mild steel ultimate shear strength ~ 250 MPa (250,000,000 N/m²), force to shear that weld ≈ stress × area you're gonna need:
- 250,000,000 × 0.0015 = (?)
- 250,000,000 × 0.001 = 250,000
- 250,000,000 × 0.0005 = 125,000
- 250,000 + 125,000 = 375,000 N (≈ 375 kN) or Class 5 (+)
3 days ago | [YT] | 14