Let the number be Y If been multiply by 4, then = Y*4 = 4Y When added by to 5 = 4Y +5=25 Then, by Subtracting 6 from both side, we have 4Y + 5 -5 = 25-5 Then, 4Y = 20 Make Y the subject of the relation. I.e divide both sides by 4 We have 4Y/4 = 20/4 Y = 5.
Damilaremathtutor
Let the numbers be X and Y
The sum,
X+Y=100 ----equ(1)
There difference
X-Y= 28 ---- equ (2)
Solve both equation simultaneously
X +Y = 100
X-Y = 28
Add equation 1 and 2
2X = 72
Divide both sides by 2
2X/2 = 72/2
X= 36.
Substitute X = 36 in equation 1.
X+Y= 100
When X = 36,
Then.
36+Y =100
Y= 100-36
Y= 64.
Therefore X= 36, Y= 64
6 months ago | [YT] | 4
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Damilaremathtutor
Let the number be Y
If been multiply by 4, then
= Y*4 = 4Y
When added by to 5
= 4Y +5=25
Then, by Subtracting 6 from both side, we have
4Y + 5 -5 = 25-5
Then, 4Y = 20
Make Y the subject of the relation. I.e divide both sides by 4
We have
4Y/4 = 20/4
Y = 5.
Let's check
If Y = 5
Then,
5*4+5 = 25
6 months ago | [YT] | 3
View 1 reply