Me Asthmatic_M@thematics.
Hey guys, Welcome to my maths channel🙏🙏
Here I do upload motivational mathematic's video and shorts, mathematician's qoutes and their biographical shorts and tutorial videoes on maths.
Here you also get many problem solution tutorial videoes related to calculus, Algebra, Trigonometry, differential equation, geometry and complex number system.
If you like to get more videoes on that topics do subscribe now and stay tuned with this channel.
Summary::
You will get here
1/ Biographical videoes of mathematician.
2/Mathematician quotes.
3/Motivational math video.
4/Basic to advance mathematics' problem and solution.
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Mail💌: themathsboy369@gmail.com
Me Asthmatic_M@thematics.
Why -> How -> what ❓
7 months ago | [YT] | 0
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Me Asthmatic_M@thematics.
Isn't it amazing 🤔 In Mathematics we study imaginary number for real application which itself exist in imaginary but they really exist😄 (Imagine a imaginary plane for imaginary number.) : ) Mathematics can go far beyond our imagination : )
Love maths ❤️...
#funthings #maths #enjoymaths #lovemaths
8 months ago | [YT] | 4
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Me Asthmatic_M@thematics.
Happy National Mathematics Day ❤️
1 year ago | [YT] | 3
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Me Asthmatic_M@thematics.
Which is more difficult??
1 year ago | [YT] | 0
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Me Asthmatic_M@thematics.
190700131099241420990620241899051417
4000
1820011802170801041718
Decrypt this message 😁...👋
1 year ago | [YT] | 1
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Me Asthmatic_M@thematics.
Dear Enthusiast, I bring for you an interesting method of finding divisors of any numbers.
Say , for n= 99 ,this can be written as n=3×3×11 by Fundamental Theorem of Arithmetic.
Now, let's say the number of divisors are expressed by d(n), then d(n)= d(p1×p2×......×pk)
= (1+1)×(1+1)×(1+1).....(1+1) (k times)
This is only for the case if exponent = 1. If exponent>1 then, d(n) = d(p1^k + p2^s+....) =( k+1)×(s+1)...
Here in my example,d(99)= d(3^2 ×11) = (2+1)× (1+1)=6.
Therefore, the number of divisors of 99 is 6 i.e 1, 3, 9, 11, 33 and 99.
If you like such type of discussion in this community then LIKE , SHARE and SUBSCRIBE . And also comment your view. 👍
Bye bye and Good night.
@measthmatic_mathematics.
1 year ago | [YT] | 4
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Me Asthmatic_M@thematics.
If a function f is partially differentiated then the function is
1 year ago | [YT] | 0
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Me Asthmatic_M@thematics.
Hey Guys , How was the day ? Today I share you something really crazy maths theorem that's given by Leonard Euler. It's something like this,
If n>= 1 and gcd (a,n)= 1, then a^phi(n) congruent to 1 (mod n). Phi(n) means the number of relatively prime numbers to n.
This is the generalized form of Fermats theorem where Fermats gave this same theorem for prime numbers.
But the main question is where we could use this all theorem. This has really crazy applications, I mean to say ,you see below I post a screenshot of a calculation that made in a digital calculator, but the same stuff could be done by using this theorem that means we can find the last digit of any large powers (a^n), where gcd(a,n) should be 1. By normal calculation we may not be able to find such things in few steps in maths without using the above theorem or if to say without our greatest mathematicians such work. We should always owe to them... 🙏
Have a good day and Good night..... ❤️
And yeah stay tuned although I am not able to upload video regularly.
1 year ago (edited) | [YT] | 8
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