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Math Mastery Quest
Evaluate the expression: [4(2x - 5) + 3(6 - x)]Solution: Distribute and simplify: [8x - 20 + 18 - 3x] Combine like terms: [5x - 2] So, the result is (5x - 2).
2 years ago | [YT] | 0
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Solve for x: 2^(3x) = 8.Comment down your answers!
Brain test33.333 + 3.0333 - 2.003 = ?
2 years ago | [YT] | 1
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If 12y - 2y = 20, what is the value of y?To solve for y in the equation 12y - 2y = 20, you can combine like terms:12y - 2y = 2010y = 20Now, divide both sides by 10 to isolate y:10y / 10 = 20 / 10y = 2So, the value of y is 2.
2 years ago (edited) | [YT] | 0
Find the equation of the line that is perpendicular to y = 2x + 3 and passes through the point (1, -4).
Only Genues Can Solve this problem 3-3x6+2 =?
Quadratic Equation:5ײ + 30× + 15 = 0?
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Math Mastery Quest
Evaluate the expression: [4(2x - 5) + 3(6 - x)]Solution: Distribute and simplify: [8x - 20 + 18 - 3x] Combine like terms: [5x - 2] So, the result is (5x - 2).
2 years ago | [YT] | 0
View 0 replies
Math Mastery Quest
#mathmethod
2 years ago | [YT] | 0
View 0 replies
Math Mastery Quest
Solve for x: 2^(3x) = 8.
Comment down your answers!
2 years ago | [YT] | 0
View 0 replies
Math Mastery Quest
Brain test
33.333 + 3.0333 - 2.003 = ?
2 years ago | [YT] | 1
View 0 replies
Math Mastery Quest
Try to learn more by visiting my Channel!
2 years ago | [YT] | 0
View 0 replies
Math Mastery Quest
This Method can help you.
2 years ago | [YT] | 0
View 1 reply
Math Mastery Quest
If 12y - 2y = 20, what is the value of y?
To solve for y in the equation 12y - 2y = 20, you can combine like terms:
12y - 2y = 20
10y = 20
Now, divide both sides by 10 to isolate y:
10y / 10 = 20 / 10
y = 2
So, the value of y is 2.
2 years ago (edited) | [YT] | 0
View 0 replies
Math Mastery Quest
Find the equation of the line that is perpendicular to y = 2x + 3 and passes through the point (1, -4).
2 years ago | [YT] | 0
View 0 replies
Math Mastery Quest
Only Genues Can Solve this problem
3-3x6+2 =?
2 years ago | [YT] | 0
View 0 replies
Math Mastery Quest
Quadratic Equation:
5ײ + 30× + 15 = 0?
2 years ago | [YT] | 0
View 0 replies
Load more